Boolean Algebra

The truth table for the following logic circuit is

For the following circuit and given inputs $A$ and $B,$ choose the correct option for output $‘Y’$

The logic performed by the circuit shown in figure is equivalent to

For the logic circuit shown, the output waveform at $\mathrm{Y}$ is

The resultant gate for the following combination is

What will be the input of $A$ and $B$ for the Boolean expression $\left(\overline{A+B}\right)·\left(\overline{A·B}\right)=1$?

What is the use of De Morgan's theorem?

The value of $A·B+\overline{A}+A$ is

The output $Y$ of the given logic circuit is,

Output $C$ of the network shown is:-

For what Boolean values of A, B & C, the given logic gate gives an output of zero.

The truth table for this given circuit is:

The output of the given circuit diagram is

Cotyledons are also called-

$\overline{\mathrm{A}\cdot \bar{\mathrm{B}}+\bar{\mathrm{A}}\cdot \mathrm{B}}$ is equivalent to

$\overline{A\cdot \bar{B}+\bar{A}\cdot B}$ is equivalent to

What is the Boolean equation for the figure?

In the given circuit, the binary inputs at $A$ and $B$ are both $1$ in one case and both $0$ in the next case. The respective outputs at $Y$ in these two cases will be

In the LOGIC gate circuit, if the value of output $\left(R\right)$ be $1$ then the inputs $X$ and $Y$ can be.

The input of $A$ and $B$ for the given Boolean expression is

$\left(\overline{A+B}\right).\left(\overline{A.B}\right)=1$